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4x^2+17x=6x-2^2
We move all terms to the left:
4x^2+17x-(6x-2^2)=0
We get rid of parentheses
4x^2+17x-6x+2^2=0
We add all the numbers together, and all the variables
4x^2+11x+4=0
a = 4; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·4·4
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{57}}{2*4}=\frac{-11-\sqrt{57}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{57}}{2*4}=\frac{-11+\sqrt{57}}{8} $
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